Answer. Simplifying the equation, we find that the compound interest is Rs. 102.50.
What is the compound interest on Rs 1000 for 18 months at 10 per annum compounded half yearly?
- Given P = 1000 R =10% compounded half yearly = 10/2 =5 t = 18 months = 1 1/2 yr. 3/2 x 2 = 3.
- CI = P ( 1 + R /100 ) ^t —P.
- CI = 1000 ( 1+ 5/100)^3 —1000.
- CI = 1000 (1.05)^3 — 1000.
- CI = 1157.62 —1000.
- CI = ₹ 157.62.
- Compound interest = ₹. 157.62.
Jan 30, 2023
What is the compound interest on Rs 1000 at 10 percent compounded annually for 2 years?
compound interest after 2yrs of 1000 Rs at the rate 10% per annum is 210 Rs. it is given that principal , P = 1000 Rs. = 210 Rs.
What is the compound interest on Rs 1000 at 10 per annum for 18 months while the interest is compounded half yearly?
1000(1.05)^3=1000*1.157625=1157.63 is amount at the end of 18 months(ie after 3 half year). So interest is 157.63Rs.
What is the compound interest on 1000 for 10 years?
Chart: Accumulated Return
xLabels | Principal | Interest |
---|---|---|
10 Years | 1,000 | 1,452.95 |
12 Years | 1,000 | 2,019.55 |
14 Years | 1,000 | 2,702.91 |
16 Years | 1,000 | 3,516.05 |
How much rs 1000 doubled in 10 years when compounded annually?
So, the amount will become Rs. 4000 in another 10 years.
What is the difference between compound interest on rupees 1000 for 1 year at 20?
Answer: Difference between compound interest on Rs 1000 for 1 year at 20% per annum when compound half yearly and quarterly is Rs 633.6. Time (t) = 1 year . =440.
How to calculate compound interest for 18 months?
Formula= A = P (1 + R/N) ^ nt
A is the final amount. P is the principal amount. r is the annual interest rate (decimal) n is the number of times interest is compounded per year (12 for monthly)